Eloise started to solve a radical equation in this way: − 3 = x − 3 + 3 = x + 3 = x + 3 − 1 = x + 3 − 1 = x + 2 ( )2 = (x − 4)2 −2x = x2 − 8x + 16 −2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 16

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Eloise working to explain a primary equation in this way:

 − 3 = x − 3 + 3 = x + 3 = x + 3− 1 = x + 3 − 1 = x + 2 ( )2 = (x − 4)2−2x = x2 − 8x + 16−2x + 2x = x2 + 8x + 16 + 2x 0 = x2 + 10x + 160 = (x + 2)(x + 8)

       x + 2 = 0               x + 8 = 0x + 2 − 2 = 0 − 2      x + 8 − 8 = 0 − 8            x = −2                  x = −8

Both solutions are outside accordingly they don't content the primary equation.

What falsity did Eloise reach? (2 points)

 a

She borrowed 2x succeeding squaring twain sides.

 b

She subtracted 1 anteriorly squaring twain sides.

 c

She factored x2 + 10x + 16 awry.

 d

She did not stop for outside solutions.

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