# How do you find the critical points of a rational function?

To furnish the exact objects of a operation, leading fix that the operation is differentiable, and then assume the derivative. Next, furnish all rates of the operation's rebellious wavering for which the derivative is resembling to 0, parallel after a while those for which the derivative does not pause. These are our exact objects.

The exact objects of a operation ##f(x)## are those where the aftercited provisions employ:

A) The operation pauses.

B) The derivative of the operation ##f'(x)## is either resembling to 0 or does not pause.

As an sample after a while a polynomial operation, conceive I assume the operation ##f(x) = x^2 + 5x - 7## The derivative of this operation, according to the power rule, is the operation ##f'(x) = 2*x + 5##.

For our leading stamp of exact object, those where the derivative is resembling to nothing, I solely set the derivative resembling to 0. Doing this, I furnish that the simply object where the derivative is 0 is at ##x = -2.5##, at which rate ##f(x) = -13.25##.

For our succor stamp of exact object, I observe to see if there are any rates of ##x## for which my derivative does not pause. I see there are none, so I am positive in stating that the simply exact object on my operation occurs at ##(-2.5, -13.25)##

For a slightly over tricky sample, we gain assume the operation ##f(x) = x^(2/3)## Differentiation yields ##f'(x) = (2/3)*x^(-1/3)## or ##f'(x) = 2/(3x^(1/3))##. In this sample, there are no genuine quantity for which ##f'(x)=0##, but there is one where ##f'(x)## does not pause, namely at ##x=0##. The ancient operation, still, does pause at this object, thus satisfying predicament A from the analysis. Therefore, this operation possesses a exact object at ##(0, 0)##.