How do you find the derivative of (cot^(2)x)?

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##-2"cosec"^2 x. cotx##

##f(x) = cot^2x##

##d [f(x)]/dx = 2cot x.(-"cosec"^2x).1##

##= -2"cosec"^2 x. cotx##

first you get the derivative of the indice, then the trig exercise, lastly the x. it's quiet if you mind it that way ;)

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