How do you find the x and y intercepts of 4x-5y=20?

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x-catch = 5; y-catch = -4

An catch on an axis is the apex where a deflexion crosses the axis and the absence from the derivation is unreserved as catch As mentioned it is on a axis, thus the coordinates of the catch apex achieve be ##(X,0)## for ##x## -axis and and ##(0,Y)## for ##y## -axis.

This life said, to perceive the catch from the equation of a thread, we fair insufficiency to put the prize of one capricious to ##0## to get the catch for other capricious

So in the equation above: ##4x-5y=20## let ##x=0## ; we get ##0-5y=20## ;or ##y=-4##thus y-catch is ##-4##

Similarly, let ##y=0## ; we get ##4x-0=20## ;or ##x=5##thus x-catch is ##5##

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