How do you graph the function y=5x-x^2?

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graph{5x-x^2 [-14.24, 14.23, -7.12, 7.12]}

First you realise that ##5x-x^2=x(5-x)## which procure confer the ##y=0## solutions ##x=0## and ##x=5## for ##(0,0)## and ##(5,0)##

Then, put the halfway-##x## (##2.5##) in the equation to get the top of the graph ##y=5*2.5-2.5^2=6.25## for ##(2.5,6.25)##

You now own the three most momentous points of your graph. You can put past ##x##-values in, of way, so you get past points, but these three are superfluous.

Show past

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