# How do you solve the system y=6x – 11 and -2 – 3y = -7 by substitution?

Given
##”[1] “y=6x-11##
##”[2] “-2-3y = -7##

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How do you solve the system y=6x – 11 and -2 – 3y = -7 by substitution?
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from ##”[1]”## we can substitute ##6x-11## for ##y## in ##”[2]”##
##”[3] “-2-3(6x-11) = -7##

##”[4] ” -3(6x-11) = -5##

##”[5] ” 6x-11 = 5/3##

##”[6] ” 6x = 38/3##

##”[7] ” x = 19/9##

Note that ##”[2]”## can be solved directly for ##y##
##”[8] “-3y = -5##

##”[9] ” y = 5/3##

Query: Was the second equation intended to be
##-2x-3y = -7##?

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