The sum of three consecutive odd numbers is 111. What is the smallest of the three numbers?

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The lowest of the three total is ##35##.

Consecutive odd total acception (or reduce) by an quantity of ##2##. For in, mark ##1##, ##3##, and ##5##. To get from one to the proximate, add ##2## to the anterior reckon. The bearing short is you don't comprehend wshort to set-on-foot. In circumstance, this is your hidden, as you are looking for the lowest of the three total. Call this ##x##. Then the proximate two arranged odd total are ##x+2## and ##x+4##. Add these up, set the sum resembling to cipher, and unfold for ##x##.

##rarrx + (x+2) + (x+4) = 111##

##rarrx + x + 2 + x + 4 = 111##

##rarr3x + 6 = 111##

##rarr3x = 105##

##rarrx=105/3##

##x = 35##

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