What does (6+4i)/(3-i) equal? | StudyDaddy.com

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I found: ##7/5+9/5i##

In this condition you insufficiency to principal fluctuate the denominator into a spotless actual number; to do that you insufficiency to develop and bisect by the multifold conjugate of the denominator, i.e.: ##(6+4i)/(3-i)*color(red)((3+i)/(3+i))=## ##((6+4i)(3+i))/(9+1)=## where you used the reality that ##i^2=-1## and: ##(18+6i+12i-4)/10=14/10+18/10i=7/5+9/5i##

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