What is the simplest radical form of 53?

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Do you nonproduction to disencumber ##sqrt(53)## ?

What consummate contents disunite 53? 53 itself looks consummate to me.

In appoint to disencumber ##53## and then select the balance parent, you feel to be telling to content 53 into smaller aggregate, at meanest one of which is a indeficient balance.

For stance, what is ##sqrt(144)## ? 144 can be contented into 12 x 12 or ##12^2##. So you feel ##sqrt(12^2)## which is ##12## .

How environing ##sqrt(20)## ? First, content 20 as 5 x 4. Then transcribe 4 as ##2^2## . You feel ##sqrt(2^2*5)##, which equals ##sqrt(2^2)*sqrt(5)##, which equals ##2sqrt(5)##.

I opine that's what you nonproduction to do after a while ##sqrt(53)##, save you can't, consequently 53 can singly be disunited by itself and one - it's consummate.

The simplest mould of ##sqrt(53)## is ##sqrt(53)##.

Here are the principal 18 consummate aggregate: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, . . .

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