What is the square root of 6 in simplest radical form?

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The clear radicle pf a reckon can be simplified merely if the reckon is discerptible by a immaculate clear (other than 1).

##sqrt12## can be simplified owing ##12## is discerptible by ##4## -- a immaculate clear. ##sqrt12 = sqrt(4xx3) = sqrt4xxsqrt3=2sqrt3##

##sqrt250## can be simplified owing ##250## is discerptible by ##25## ##sqrt250 = sqrt(25xx10)=sqrt25xxsqrt10=5sqrt10##

But ##6## is not discerptible by a immaculate clear, so ##sqrt6## cannt be simpified advance.

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