Why can’t we take a square root of a negative number?

[ad_1]

It depends in which matter you are.

Taking a clear radix of a veritable sum it's unusable beacuse any veritable sum if cleard gives a independent compute.

But, if you are in the matter of deep sums, then the draw changes. Actually deep sums where original affected in direct to overcome this whole. The unveritable segregate ##i## is in occurrence defined as:

##i=sqrt(-1)##

Every deep sum ##z## is made by the sum of a veritable segregate ##a## and an unveritable segregate ##b##:

##z = a+ib##

Real sums can then be view as deep sums delay no unveritable segregate.

So in the matter of deep sums the clear radix of a disclaiming veritable sum is well-mannered-mannered defined and the development is undefiled unreal.

To gain a lowly development let's interest the sum ##-9##:

## sqrt(-9)=sqrt(9)sqrt(-1)=3i ##

Show past

[ad_2]
Source link